What is inverse oflaplace (0.6)/(s+2) ?

The answer to inverse oflaplace (0.6)/(s+2) is 0.6e^{-2t}

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inverse oflaplace (0.6)/(s+2)

inverse laplace

\frac{0.6}{s + 2}

0.6 e^{- 2 t}

Solution steps

L^{- 1} {\frac{0.6}{s + 2}}

= L^{- 1} {0.6 \cdot \frac{1}{s + 2}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 0.6 L^{- 1} {\frac{1}{s + 2}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s + 2}} = e^{- 2 t}

= 0.6 e^{- 2 t}

\frac{d y}{d x} = \frac{( x ^{2} y - y )}{( y + 1 )}, y (0) = 1

\int e^{u} d u

\int \frac{( x - 1 ) ^{3}}{2 x} d x

\int 4 x^{3} (x^{4} + 5)^{6} d x

x \to + 1 + lim (1 - x^{2})

What is inverse oflaplace (0.6)/(s+2) ?
The answer to inverse oflaplace (0.6)/(s+2) is 0.6e^{-2t}