What is (\partial)/(\partial y)(xe^{2y}sin(7z)) ?

The answer to (\partial)/(\partial y)(xe^{2y}sin(7z)) is xsin(7z)e^{2y}*2

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(\partial)/(\partial y)(xe^{2y}sin(7z))

\frac{\partial}{\partial y} (x e^{2 y} sin (7 z))

x sin (7 z) e^{2 y} \cdot 2

Solution steps

\frac{\partial}{\partial y} (x e^{2 y} sin (7 z))

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x sin (7 z) \frac{\partial}{\partial y} (e^{2 y})

Apply the chain rule:

e^{2 y} \frac{\partial}{\partial y} (2 y)

= e^{2 y} \frac{\partial}{\partial y} (2 y)

\frac{\partial}{\partial y} (2 y) = 2

= x sin (7 z) e^{2 y} \cdot 2

24 x - 0.01 x^{2}

y^{^{''}} + 121 y = sec (11 x)

x \to 0 - lim (\frac{1 - e ^{- 3 x}}{x})

\frac{d}{d x} (\frac{e ^{x}}{7 x ^{2} + 8})

What is (\partial)/(\partial y)(xe^{2y}sin(7z)) ?
The answer to (\partial)/(\partial y)(xe^{2y}sin(7z)) is xsin(7z)e^{2y}*2