What is the limit as x approaches-1 of 1/(x^2+1) ?

The limit as x approaches-1 of 1/(x^2+1) is 1/2

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limit as x approaches-1 of 1/(x^2+1)

x \to - 1 lim (\frac{1}{x ^{2} + 1})

\frac{1}{2}

Solution steps

x \to - 1 lim (\frac{1}{x ^{2} + 1})

Plug in the value

x = - 1

= \frac{1}{( - 1 ) ^{2} + 1}

(- 1)^{2} + 1 = 2

= \frac{1}{2}

n = 0 \sum \infty \frac{6}{5 ^{n}}

\int 2 sec (2 x) tan (2 x) d x

y^{^{'}} + (\frac{1}{x}) y = 8 x^{2}

\int_{2}^{4} x^{2} y + y^{2} x + x + y d x

\frac{1}{1 + x ^{- 1}}

What is the limit as x approaches-1 of 1/(x^2+1) ?
The limit as x approaches-1 of 1/(x^2+1) is 1/2