What is the derivative of-16x^2 ?

The derivative of-16x^2 is -32x

What is the first derivative of-16x^2 ?

The first derivative of-16x^2 is -32x

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\frac{d}{d x} (- 16 x^{2})

- 32 x

Solution steps

\frac{d}{d x} (- 16 x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 16 \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 16 \cdot 2 x^{2 - 1}

Simplify

= - 32 x

\frac{\partial}{\partial z} (9 z e^{x yz})

\frac{d}{d x} ((1 + cos (x)) sin (x))

\frac{4}{( s + 2 ) ^{3}}

x \to 0 lim ((3 x + 1))