What is (\partial)/(\partial x)(ln(x+5y+6z)) ?

The answer to (\partial)/(\partial x)(ln(x+5y+6z)) is 1/(x+5y+6z)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(ln(x+5y+6z))

\frac{\partial}{\partial x} (ln (x + 5 y + 6 z))

\frac{1}{x + 5 y + 6 z}

Solution steps

\frac{\partial}{\partial x} (ln (x + 5 y + 6 z))

Treat

y, z

as constants

Apply the chain rule:

\frac{1}{x + 5 y + 6 z} \frac{\partial}{\partial x} (x + 5 y + 6 z)

= \frac{1}{x + 5 y + 6 z} \frac{\partial}{\partial x} (x + 5 y + 6 z)

\frac{\partial}{\partial x} (x + 5 y + 6 z) = 1

= \frac{1}{x + 5 y + 6 z} \cdot 1

Simplify

= \frac{1}{x + 5 y + 6 z}

\frac{d}{d x} (x sec (x))

\int (cos (θ)) d θ

x^{3} - 3 x + 4

\int \frac{x ^{3}}{x ^{2} + 1} d x

\frac{\partial}{\partial x} (x^{1} y^{2} + y^{4} z^{5})

What is (\partial)/(\partial x)(ln(x+5y+6z)) ?
The answer to (\partial)/(\partial x)(ln(x+5y+6z)) is 1/(x+5y+6z)