What is the integral of e^{(3-x)} ?

The integral of e^{(3-x)} is -e^{3-x}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^{(3-x)}

\int e^{(3 - x)} d x

- e^{3 - x} + C

Solution steps

\int e^{3 - x} d x

Apply u-substitution

: \int - e^{u} d u

= \int - e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= - e^{u}

Substitute back

u = 3 - x

= - e^{3 - x}

Add a constant to the solution

= - e^{3 - x} + C

x^{^{''}} + x = 0

2 x^{2} + 1

\int \frac{1}{2} (e^{x} + e^{- x}) d x

\frac{d y}{d x} (x) = y + (x^{2} - 3)^{2}

n = 1 \sum \infty \frac{n !}{n}