What is the integral of e^{5x+6} ?

The integral of e^{5x+6} is 1/5 e^{5x+6}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^{5x+6}

\int e^{5 x + 6} d x

\frac{1}{5} e^{5 x + 6} + C

Solution steps

\int e^{5 x + 6} d x

Apply u-substitution

: \int e^{u} \frac{1}{5} d u

= \int e^{u} \frac{1}{5} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{5} e^{u}

Substitute back

u = 5 x + 6

= \frac{1}{5} e^{5 x + 6}

Add a constant to the solution

= \frac{1}{5} e^{5 x + 6} + C

y^{^{''}} - 3 y^{^{'}} + 2 y = e^{2 t}

f (x) = x - 2 sin (x), at x = 0

x y^{^{''}} - y^{^{'}} = x^{2}

\frac{x - 5}{x ^{2} + 1}

\frac{d}{d x} (\frac{24}{x ^{4}})