What is the derivative of (1+x^2)^2 ?

The derivative of (1+x^2)^2 is 4x(1+x^2)

What is the first derivative of (1+x^2)^2 ?

The first derivative of (1+x^2)^2 is 4x(1+x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

(1 + x^{2})^{2}

4 x (1 + x^{2})

Solution steps

\frac{d}{d x} ((1 + x^{2})^{2})

Apply the chain rule:

2 (1 + x^{2}) \frac{d}{d x} (1 + x^{2})

= 2 (1 + x^{2}) \frac{d}{d x} (1 + x^{2})

\frac{d}{d x} (1 + x^{2}) = 2 x

= 2 (1 + x^{2}) \cdot 2 x

Simplify

= 4 x (1 + x^{2})

\int (7 x^{5} + 6 x^{4} - 3 x^{3} - 9 x + 5) d x

\int \frac{x ^{2} - 64}{x ( x - 1 ) ^{2}} d x

\int \frac{1}{y 1 + ( ln ( y ) ) ^{2}} d y

y = \frac{( x ^{2} + 1 )}{( x ^{3} - 1 )}

\int sec (t) (8 sec (t) + 5 tan (t)) d t

What is the derivative of (1+x^2)^2 ?
The derivative of (1+x^2)^2 is 4x(1+x^2)
What is the first derivative of (1+x^2)^2 ?
The first derivative of (1+x^2)^2 is 4x(1+x^2)