What is the integral from 1 to sqrt(2 of)x3^{(x^2)} ?

The integral from 1 to sqrt(2 of)x3^{(x^2)} is 3/(ln(3))

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integral from 1 to sqrt(2 of)x3^{(x^2)}

\int_{1}^{2} x 3^{(x^{2})} d x

\frac{3}{ln ( 3 )}

Solution steps

\int_{1}^{2} x \cdot 3^{x^{2}} d x

Apply u-substitution

: \int_{3}^{9} \frac{1}{2 ln ( 3 )} d u

= \int_{3}^{9} \frac{1}{2 ln ( 3 )} d u

Integral of a constant:

\int a d x = a x

= [\frac{1}{2 ln ( 3 )} u]_{3}^{9}

Compute the boundaries:

\frac{3}{ln ( 3 )}

= \frac{3}{ln ( 3 )}

(x^{2} + y^{2}) d x + x y d y = 0

\frac{\partial}{\partial x} (- y sin (x ln (y)) ln (y))

x \to e lim (- 11 - 12)

y = x + 12

2 x - 1 + (3 y + 7) \frac{d y}{d x} = 0

What is the integral from 1 to sqrt(2 of)x3^{(x^2)} ?
The integral from 1 to sqrt(2 of)x3^{(x^2)} is 3/(ln(3))