What is (\partial)/(\partial x)(x^3-3xy^2) ?

The answer to (\partial)/(\partial x)(x^3-3xy^2) is 3x^2-3y^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(x^3-3xy^2)

\frac{\partial}{\partial x} (x^{3} - 3 x y^{2})

3 x^{2} - 3 y^{2}

Solution steps

\frac{\partial}{\partial x} (x^{3} - 3 x y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{3}) - \frac{\partial}{\partial x} (3 x y^{2})

\frac{\partial}{\partial x} (x^{3}) = 3 x^{2}

\frac{\partial}{\partial x} (3 x y^{2}) = 3 y^{2}

= 3 x^{2} - 3 y^{2}

\frac{d}{d x} (\frac{2}{1 - x ^{2}})

\int \frac{1}{2 x - 1} d x

\frac{d}{d x} (\frac{5 1 - x ^{3}}{6})

\int 13 arctan (x) d x

x \to + 0 lim (\frac{e ^{2 x} - 1}{sin ( 3 x )})

What is (\partial)/(\partial x)(x^3-3xy^2) ?
The answer to (\partial)/(\partial x)(x^3-3xy^2) is 3x^2-3y^2