What is area y= 2/(1+x^2),y=|x| ?

The answer to area y= 2/(1+x^2),y=|x| is (2pi-2)/2

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area y= 2/(1+x^2),y=|x|

area

y = \frac{2}{1 + x ^{2}}, y = ∣ x ∣

\frac{2 π - 2}{2}

Solution steps

Apply the area formula:

\int_{- 1}^{1} \frac{2}{1 + x ^{2}} - ∣ x ∣ d x

Solve

\int_{- 1}^{1} \frac{2}{1 + x ^{2}} - ∣ x ∣ d x : \frac{2 π - 2}{2}

The area is:

= \frac{2 π - 2}{2}

\int \frac{2 x}{4 - x ^{2}} d x

\int 4 e^{7 x} d x

\frac{d y}{d x} = x^{4} y^{- 7}

\frac{d}{d x} (2 x^{2} - 3 x + 3)

x \to 0 lim (2 x - 1)

What is area y= 2/(1+x^2),y=|x| ?
The answer to area y= 2/(1+x^2),y=|x| is (2pi-2)/2