What is the tangent of y=9x-4x^2,(-2,-34) ?

The tangent of y=9x-4x^2,(-2,-34) is y=25x+16

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tangent of y=9x-4x^2,(-2,-34)

tangent of

y = 9 x - 4 x^{2}, (- 2, - 34)

y = 25 x + 16

Solution steps

Find the slope of

y = 9 x - 4 x^{2} : \frac{d y}{d x} = 9 - 8 x

Compute the slope of

y = 9 x - 4 x^{2}

(- 2, - 34) : m = 25

Find the line with slope m=

25

and passing through

(- 2, - 34) : y = 25 x + 16

y = 25 x + 16

\int \frac{cos ( \frac{π}{x ^{5}} )}{x ^{6}} d x

\int sin (ln (x)) d x

\int 0.5 x d x

y^{^{''}} + 9 y = cos (3 x)

x \to - 8 lim (x (8))

What is the tangent of y=9x-4x^2,(-2,-34) ?
The tangent of y=9x-4x^2,(-2,-34) is y=25x+16