What is (\partial)/(\partial z)(tan(3+2x^2y^3z^2)) ?

The answer to (\partial)/(\partial z)(tan(3+2x^2y^3z^2)) is sec^2(3+2x^2y^3z^2)*4x^2y^3z

Popular >

(\partial)/(\partial z)(tan(3+2x^2y^3z^2))

\frac{\partial}{\partial z} (tan (3 + 2 x^{2} y^{3} z^{2}))

sec^{2} (3 + 2 x^{2} y^{3} z^{2}) \cdot 4 x^{2} y^{3} z

Solution steps

\frac{\partial}{\partial z} (tan (3 + 2 x^{2} y^{3} z^{2}))

Treat

x, y

as constants

Apply the chain rule:

sec^{2} (3 + 2 x^{2} y^{3} z^{2}) \frac{\partial}{\partial z} (3 + 2 x^{2} y^{3} z^{2})

= sec^{2} (3 + 2 x^{2} y^{3} z^{2}) \frac{\partial}{\partial z} (3 + 2 x^{2} y^{3} z^{2})

\frac{\partial}{\partial z} (3 + 2 x^{2} y^{3} z^{2}) = 4 x^{2} y^{3} z

= sec^{2} (3 + 2 x^{2} y^{3} z^{2}) \cdot 4 x^{2} y^{3} z

(2 x + 1)^{\frac{1}{5}}, at x = 2

n = 0 \sum \infty \frac{n}{( n ^{2} + 3 )}

\frac{d}{d y} (2 x y)

f (x) = - \frac{12}{s ^{5}}

\frac{4}{3} π \cdot r^{2}

What is (\partial)/(\partial z)(tan(3+2x^2y^3z^2)) ?
The answer to (\partial)/(\partial z)(tan(3+2x^2y^3z^2)) is sec^2(3+2x^2y^3z^2)*4x^2y^3z