What is the first d/(dy)(1-x^2y) ?

The first d/(dy)(1-x^2y) is -x^2

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d/(dy)(1-x^2y)

\frac{d}{d y} (1 - x^{2} y)

- x^{2}

Solution steps

\frac{d}{d y} (1 - x^{2} y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d y} (1) - \frac{d}{d y} (x^{2} y)

\frac{d}{d y} (1) = 0

\frac{d}{d y} (x^{2} y) = x^{2}

= 0 - x^{2}

Simplify

= - x^{2}

n \to \infty lim (9)

\frac{d}{d x} (- 12 x^{2} - 16 x + 16)

\frac{d}{d x} (x^{\frac{9}{10}})

\frac{d P}{d t} + 2 tP = P + 4 t - 2

n = 1 \sum \infty n^{5} (1 + n^{6})^{5}