What is the tangent of f(x)=csc(x),\at x= pi/6 ?

The tangent of f(x)=csc(x),\at x= pi/6 is y=-2sqrt(3)x+2+pi/(sqrt(3))

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tangent of f(x)=csc(x),\at x= pi/6

tangent of

f (x) = csc (x), at x = \frac{π}{6}

y = - 23 x + 2 + \frac{π}{3}

Solution steps

Find the tangent point:

(\frac{π}{6}, 2)

Find the slope of

f (x) = csc (x) : \frac{df ( x )}{d x} = - cot (x) csc (x)

Compute the slope of

f (x) = csc (x)

x = \frac{π}{6} : m = - 23

Find the line with slope m=

- 23

and passing through

(\frac{π}{6}, 2) : y = - 23 x + 2 + \frac{π}{3}

y = - 23 x + 2 + \frac{π}{3}

\frac{d}{d x} (y^{3} + x y^{2} + y)

\frac{( x + 1 ) ( x ^{2} + 1 )}{x - 2}

\int_{- 1}^{1} (6 x^{5} + 3) d x

y = \frac{9 x}{e ^{x}}

f (x) = \frac{x + 1}{x ^{2} + 1}

What is the tangent of f(x)=csc(x),\at x= pi/6 ?
The tangent of f(x)=csc(x),\at x= pi/6 is y=-2sqrt(3)x+2+pi/(sqrt(3))