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Popular >

y^'=(x-3)e^{-2y}

Solution

y^{^{'}} = (x - 3) e^{- 2 y}

Solution

y = \frac{ln ( x ^{2} - 6 x + c _{1} )}{2}

Solution steps

y^{'} (x) = (x - 3) e^{- 2 y}

Solve separable ODE:

y = \frac{ln ( x ^{2} - 6 x + c _{1} )}{2}

y = \frac{ln ( x ^{2} - 6 x + c _{1} )}{2}

Popular Examples

derivative of-4/((5)^3)derivative of

- \frac{4}{( 5 ) ^{3}}

limit as x approaches-1 of x^2-x+7

x \to - 1 lim (x^{2} - x + 7)

derivative of f(x)=ln(3+sqrt(x))derivative of

f (x) = ln (3 + x)

(dy)/(dx)=(y^2+6xsqrt(x^2+y^2))/(xy)

\frac{d y}{d x} = \frac{y ^{2} + 6 x x ^{2} + y ^{2}}{x y}

tangent of f(x)=2(x^2-1)^3,\at x=2 tangent of

f (x) = 2 (x^{2} - 1)^{3}, at x = 2

Frequently Asked Questions (FAQ)

What is the solution for y^'=(x-3)e^{-2y} ?
The solution for y^'=(x-3)e^{-2y} is y=(ln(x^2-6x+c_{1}))/2