What is the solution for y^{''}+3y=9 ?

The solution for y^{''}+3y=9 is y=c_{1}cos(sqrt(3)t)+c_{2}sin(sqrt(3)t)+3

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y^{''}+3y=9

y^{^{''}} + 3 y = 9

y = c_{1} cos (3 t) + c_{2} sin (3 t) + 3

Solution steps

y^{''} (t) + 3 y = 9

Solve linear ODE:

y = c_{1} cos (3 t) + c_{2} sin (3 t) + 3

y = c_{1} cos (3 t) + c_{2} sin (3 t) + 3

\frac{d}{d x} (\frac{x ^{2} + 3}{x ^{2} - 3 x})

\int 4 r^{2} + 1 r d r

\frac{d}{d x} (arccos (\frac{x}{8}))

\frac{d}{d x} (π^{x})

\int \frac{1}{x 9 x ^{2} - 25} d x

What is the solution for y^{''}+3y=9 ?
The solution for y^{''}+3y=9 is y=c_{1}cos(sqrt(3)t)+c_{2}sin(sqrt(3)t)+3