What is (\partial)/(\partial u)(u/(v+1)) ?

The answer to (\partial)/(\partial u)(u/(v+1)) is 1/(v+1)

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(\partial)/(\partial u)(u/(v+1))

\frac{\partial}{\partial u} (\frac{u}{v + 1})

\frac{1}{v + 1}

Solution steps

\frac{\partial}{\partial u} (\frac{u}{v + 1})

Treat

v

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{v + 1} \frac{\partial}{\partial u} (u)

Apply the common derivative:

\frac{\partial}{\partial u} (u) = 1

= \frac{1}{v + 1} \cdot 1

Simplify

= \frac{1}{v + 1}

\int g e^{- 2 c t} d t

x \to - 1 lim (\frac{x + 1}{1 - x ^{2}})

x \to 5 + lim (\frac{5}{x - 5})

\int cos (2 x) sin (3 x) d x

x^{\frac{1}{3}}, 8

What is (\partial)/(\partial u)(u/(v+1)) ?
The answer to (\partial)/(\partial u)(u/(v+1)) is 1/(v+1)