What is the tangent of y=8xsin(x),(pi/2 ,4pi) ?

The tangent of y=8xsin(x),(pi/2 ,4pi) is y=8x

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tangent of y=8xsin(x),(pi/2 ,4pi)

tangent of

y = 8 x sin (x), (\frac{π}{2}, 4 π)

y = 8 x

Solution steps

Find the slope of

y = 8 x sin (x) : \frac{d y}{d x} = 8 (sin (x) + x cos (x))

Compute the slope of

y = 8 x sin (x)

(\frac{π}{2}, 4 π) : m = 8

Find the line with slope m=

8

and passing through

(\frac{π}{2}, 4 π) : y = 8 x

y = 8 x

y = \frac{1}{x ^{5}}, (1, 1)

\frac{\partial}{\partial x} ((x_{1} + y_{2})^{2})

3 x + 2

\frac{2}{( s + 2 ) ( s + 1 )}

\int e^{8 x + e^{8 x}} d x

What is the tangent of y=8xsin(x),(pi/2 ,4pi) ?
The tangent of y=8xsin(x),(pi/2 ,4pi) is y=8x