What is the d/(dθ)(tan^2(θ)) ?

The d/(dθ)(tan^2(θ)) is 2tan(θ)sec^2(θ)

What is the first d/(dθ)(tan^2(θ)) ?

The first d/(dθ)(tan^2(θ)) is 2tan(θ)sec^2(θ)

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\frac{d}{d θ} (tan^{2} (θ))

2 tan (θ) sec^{2} (θ)

Solution steps

\frac{d}{d θ} (tan^{2} (θ))

Apply the chain rule:

2 tan (θ) \frac{d}{d θ} (tan (θ))

= 2 tan (θ) \frac{d}{d θ} (tan (θ))

\frac{d}{d θ} (tan (θ)) = sec^{2} (θ)

= 2 tan (θ) sec^{2} (θ)

y^{^{''}} + 11 y^{^{'}} + 24 y = 0, y (0) = 0, y^{^{'}} (0) = - 7

x \to 0 lim (\frac{( 9 ^{x} - 3 ^{x} )}{x})

\int x \cdot ln^{3} (x) d x

x \to 2 lim (2 x^{2} - 3 x + 5)

\frac{s ^{2}}{( s ^{2} + \frac{1}{4} )}

What is the d/(dθ)(tan^2(θ)) ?
The d/(dθ)(tan^2(θ)) is 2tan(θ)sec^2(θ)
What is the first d/(dθ)(tan^2(θ)) ?
The first d/(dθ)(tan^2(θ)) is 2tan(θ)sec^2(θ)