What is the limit as x approaches 0+of 2xe^{-3x} ?

The limit as x approaches 0+of 2xe^{-3x} is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0+of 2xe^{-3x}

x \to 0 + lim (2 x e^{- 3 x})

0

Solution steps

x \to 0 + lim (2 x e^{- 3 x})

Plug in the value

x = 0

= 2 \cdot 0 \cdot e^{- 3 \cdot 0}

Simplify

= 0

\int_{0}^{16} \frac{500 x}{x ^{2} + 24} d x

5 π x^{2}

\frac{\partial}{\partial x} (40 x^{\frac{3}{4}} y^{\frac{1}{4}})

y = x^{3}, x = - 1

f (x) = (x^{3} + 1) (x^{2} - 2), at x = 2

What is the limit as x approaches 0+of 2xe^{-3x} ?
The limit as x approaches 0+of 2xe^{-3x} is 0