What is the limit as x approaches 3 of (x^2-8)/(x-3) ?

The limit as x approaches 3 of (x^2-8)/(x-3) is diverges

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limit as x approaches 3 of (x^2-8)/(x-3)

x \to 3 lim (\frac{x ^{2} - 8}{x - 3})

diverges

Solution steps

x \to 3 lim (\frac{x ^{2} - 8}{x - 3})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 3 + lim (\frac{x ^{2} - 8}{x - 3}) = \infty

x \to 3 - lim (\frac{x ^{2} - 8}{x - 3}) = - \infty

= diverges

\frac{d}{d x} (x - 3 x^{2} + 8 x^{- 2})

\frac{d y}{d x} = y + 4 y \cdot cos (2 x)

\int - 1728 - x^{3} d x

\int_{4}^{8} \frac{5}{12 - x} d x

\frac{d}{d x} ((arctan (5 x))^{2})

What is the limit as x approaches 3 of (x^2-8)/(x-3) ?
The limit as x approaches 3 of (x^2-8)/(x-3) is diverges