What is the slope of 1/3*t^3-9*t+2 ?

The slope of 1/3*t^3-9*t+2 is t^2-9

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slope of 1/3t^3-9t+2

slope

\frac{1}{3} \cdot t^{3} - 9 \cdot t + 2

t^{2} - 9

Solution steps

\frac{1}{3} t^{3} - 9 t + 2

In order to find the slope of the function, take the derivative of

\frac{1}{3} t^{3} - 9 t + 2

\frac{d}{d t} (\frac{1}{3} t^{3} - 9 t + 2) = t^{2} - 9

t^{2} - 9

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