What is the solution for y^{''}+9y=26e^{2x} ?

The solution for y^{''}+9y=26e^{2x} is y=c_{1}cos(3x)+c_{2}sin(3x)+2e^{2x}

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y^{''}+9y=26e^{2x}

y^{^{''}} + 9 y = 26 e^{2 x}

y = c_{1} cos (3 x) + c_{2} sin (3 x) + 2 e^{2 x}

Solution steps

y^{''} (x) + 9 y = 26 e^{2 x}

Solve linear ODE:

y = c_{1} cos (3 x) + c_{2} sin (3 x) + 2 e^{2 x}

y = c_{1} cos (3 x) + c_{2} sin (3 x) + 2 e^{2 x}

\int_{0}^{5} π (2 3 y)^{2} d y

\frac{2 s}{1 + 2 s}

\int \frac{x ^{4} + 2}{x ^{2}} d x

f (x) = x - 3, (7, 2)

\frac{d}{d x} (- \frac{6 x}{y})

What is the solution for y^{''}+9y=26e^{2x} ?
The solution for y^{''}+9y=26e^{2x} is y=c_{1}cos(3x)+c_{2}sin(3x)+2e^{2x}