What is the integral from 0 to infinity of 5e^{-5x} ?

The integral from 0 to infinity of 5e^{-5x} is 1

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integral from 0 to infinity of 5e^{-5x}

\int_{0}^{\infty} 5 e^{- 5 x} d x

1

Solution steps

\int_{0}^{\infty} 5 e^{- 5 x} d x

Compute the indefinite integral:

\int 5 e^{- 5 x} d x = - e^{- 5 x} + C

Compute the boundaries:

\int_{0}^{\infty} 5 e^{- 5 x} d x = 0 - (- 1)

= 0 - (- 1)

Simplify

= 1

\frac{d}{d x} (4 x^{3} - 3 1 + 2 x)

\frac{d y}{d x}, y = x^{2}

f (t) = e^{2 t}

\int t^{3} \cdot 9 t^{4} + 1 d t

\int_{1}^{t} \frac{9}{x ^{3}} d x

What is the integral from 0 to infinity of 5e^{-5x} ?
The integral from 0 to infinity of 5e^{-5x} is 1