What is (\partial)/(\partial x)(sin(4x+4y)) ?

The answer to (\partial)/(\partial x)(sin(4x+4y)) is cos(4x+4y)*4

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(\partial)/(\partial x)(sin(4x+4y))

\frac{\partial}{\partial x} (sin (4 x + 4 y))

cos (4 x + 4 y) \cdot 4

Solution steps

\frac{\partial}{\partial x} (sin (4 x + 4 y))

Treat

y

as a constant

Apply the chain rule:

cos (4 x + 4 y) \frac{\partial}{\partial x} (4 x + 4 y)

= cos (4 x + 4 y) \frac{\partial}{\partial x} (4 x + 4 y)

\frac{\partial}{\partial x} (4 x + 4 y) = 4

= cos (4 x + 4 y) \cdot 4

\frac{d}{d x} ((1 - x^{2})^{5})

f (x) = csc (x^{2})

\int \frac{- y}{1 + y ^{2}} d y

\int_{0}^{2} \frac{1}{4 - x ^{2}} d x

(e^{y} + 6 x) d x + x e^{y} d y = 0

What is (\partial)/(\partial x)(sin(4x+4y)) ?
The answer to (\partial)/(\partial x)(sin(4x+4y)) is cos(4x+4y)*4