What is the integral of-cos(x)+Cx+C ?

The integral of-cos(x)+Cx+C is -sin(x)+(Cx^2)/2+Cx+C

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integral of-cos(x)+Cx+C

\int - cos (x) + C x + C d x

- sin (x) + \frac{C x ^{2}}{2} + C x + C

Solution steps

\int - cos (x) + C x + C d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int cos (x) d x + \int C x d x + \int C d x

\int cos (x) d x = sin (x)

\int C x d x = \frac{C x ^{2}}{2}

\int C d x = C x

= - sin (x) + \frac{C x ^{2}}{2} + C x

Add a constant to the solution

= - sin (x) + \frac{C x ^{2}}{2} + C x + C

f (x) = 4 x - 5

\frac{d}{d x} (\frac{9 - x e ^{x}}{x + e ^{x}})

\frac{x ^{2}}{8}

\int_{- 1}^{1} ∣ x ∣ - x d x

\int_{1}^{16} \frac{1}{7 - x} d x

What is the integral of-cos(x)+Cx+C ?
The integral of-cos(x)+Cx+C is -sin(x)+(Cx^2)/2+Cx+C