What is the integral of (\sqrt[3]{y})^2 ?

The integral of (\sqrt[3]{y})^2 is 3/5 y^{5/3}+C

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integral of (\sqrt[3]{y})^2

\frac{3}{5} y^{\frac{5}{3}} + C

Solution steps

Apply Integration By Parts

\int \frac{2}{3} y^{\frac{2}{3}} d y = \frac{2}{5} y^{\frac{5}{3}}

Simplify

= \frac{3}{5} y^{\frac{5}{3}}

Add a constant to the solution

= \frac{3}{5} y^{\frac{5}{3}} + C

arctan (\frac{x}{5})

\int_{- 1}^{0} \frac{1}{x ^{3}} d x

\frac{d}{d x} ((\frac{1}{x ^{2}} - \frac{6}{x ^{4}}) (x + 8 x^{3}))

x \to 1 lim (\frac{0}{x ^{2} - 1})

\int (18 x + 5) d x

What is the integral of (\sqrt[3]{y})^2 ?
The integral of (\sqrt[3]{y})^2 is 3/5 y^{5/3}+C