What is (\partial)/(\partial x)(ln(2x+1)) ?

The answer to (\partial)/(\partial x)(ln(2x+1)) is 2/(2x+1)

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(\partial)/(\partial x)(ln(2x+1))

\frac{\partial}{\partial x} (ln (2 x + 1))

\frac{2}{2 x + 1}

Solution steps

\frac{\partial}{\partial x} (ln (2 x + 1))

Apply the chain rule:

\frac{1}{2 x + 1} \frac{\partial}{\partial x} (2 x + 1)

= \frac{1}{2 x + 1} \frac{\partial}{\partial x} (2 x + 1)

\frac{\partial}{\partial x} (2 x + 1) = 2

= \frac{1}{2 x + 1} \cdot 2

Simplify

\frac{1}{2 x + 1} \cdot 2 : \frac{2}{2 x + 1}

= \frac{2}{2 x + 1}

(e^{t} - e^{- t})^{2}

\int 512 x^{2} cos (8 x) d x

\frac{d}{d x} (ln (\frac{sin ( x )}{x}))

y = 4 ln (x), y = x ln (x)

x \to 4 lim (e^{\frac{3}{4 - x}})

What is (\partial)/(\partial x)(ln(2x+1)) ?
The answer to (\partial)/(\partial x)(ln(2x+1)) is 2/(2x+1)