en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 0 of |x^2-1|

Solution

\int_{- 1}^{0} x^{2} - 1 d x

Solution

\frac{2}{3}

+1

Solution steps

\int_{- 1}^{0} x^{2} - 1 d x

Eliminate Absolutes

= \int_{- 1}^{0} - x^{2} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 1}^{0} x^{2} d x + \int_{- 1}^{0} 1 d x

\int_{- 1}^{0} x^{2} d x = \frac{1}{3}

\int_{- 1}^{0} 1 d x = 1

= - \frac{1}{3} + 1

Simplify

- \frac{1}{3} + 1 : \frac{2}{3}

= \frac{2}{3}

Popular Examples

limit as x approaches-9+of 1/(x+9)

x \to - 9 + lim (\frac{1}{x + 9})

tangent of y=6x^2-x^3(1.5)tangent of

y = 6 x^{2} - x^{3} (1.5)

limit as x approaches 0 of 1-x^2

x \to 0 lim (1 - x^{2})

integral of x/((1+x)^2)

\int \frac{x}{( 1 + x ) ^{2}} d x

sqrt(x)+sqrt(y)y^'=0,y(1)=9

x + y y^{^{'}} = 0, y (1) = 9

Frequently Asked Questions (FAQ)

What is the integral from-1 to 0 of |x^2-1| ?
The integral from-1 to 0 of |x^2-1| is 2/3