What is the tangent of y=50-x^2 ?

The tangent of y=50-x^2 is y=-2a_{0}x+50+a_{0}^2

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tangent of y=50-x^2

tangent of

y = 50 - x^{2}

y = - 2 a_{0} x + 50 + a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 50 - a_{0}^{2})

Find the slope of

y = 50 - x^{2} : \frac{d y}{d x} = - 2 x

Compute the slope of

y = 50 - x^{2}

x = a_{0} : m = - 2 a_{0}

Find the line with slope m=

- 2 a_{0}

and passing through

(a_{0}, 50 - a_{0}^{2}) : y = - 2 a_{0} x + 50 + a_{0}^{2}

y = - 2 a_{0} x + 50 + a_{0}^{2}

f (x) = 3 cos (x)

x \to - 5 + lim (\frac{1}{x ^{2} - 25})

(t^{2} + 2 t) \frac{d x}{d t} = 2 x + 6, x (1) = 1

y^{^{''}} + 7 y = 0

\frac{d}{d x} (e^{3 x} + 3 x e^{3 x})

What is the tangent of y=50-x^2 ?
The tangent of y=50-x^2 is y=-2a_{0}x+50+a_{0}^2