What is the integral from 0 to 3 of-x^2 ?

The integral from 0 to 3 of-x^2 is -9

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integral from 0 to 3 of-x^2

\int_{0}^{3} - x^{2} d x

- 9

Solution steps

\int_{0}^{3} - x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{0}^{3} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{3}

= - [\frac{x ^{3}}{3}]_{0}^{3}

Compute the boundaries:

9

= - 9

\int tan (3 x) sec^{\frac{5}{4}} (3 x) d x

y = x, (36, 6)

\frac{d}{d x} (lo g_{13} (x))

f (x) = 8 x^{2} cot (x)

\frac{d}{d t} (\frac{t}{1 + t})