What is (\partial)/(\partial x)(3x^2+y^2) ?

The answer to (\partial)/(\partial x)(3x^2+y^2) is 6x

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(\partial)/(\partial x)(3x^2+y^2)

\frac{\partial}{\partial x} (3 x^{2} + y^{2})

6 x

Solution steps

\frac{\partial}{\partial x} (3 x^{2} + y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2}) + \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (y^{2}) = 0

= 6 x + 0

Simplify

= 6 x

y = 3 x^{2} + e^{2} x + π^{2}

y = (1 + 4 (2))^{\frac{3}{2}}

\int_{0}^{x} 36 - t^{2} d t

\frac{d}{d x} ((2 x^{5} - 3)^{8})

\frac{d}{d x} (4 e^{\frac{x}{2}})

What is (\partial)/(\partial x)(3x^2+y^2) ?
The answer to (\partial)/(\partial x)(3x^2+y^2) is 6x