What is the derivative of tan^2(3x)+1 ?

The derivative of tan^2(3x)+1 is 6sec^2(3x)tan(3x)

What is the first derivative of tan^2(3x)+1 ?

The first derivative of tan^2(3x)+1 is 6sec^2(3x)tan(3x)

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derivative of

tan^{2} (3 x) + 1

6 sec^{2} (3 x) tan (3 x)

Solution steps

\frac{d}{d x} (tan^{2} (3 x) + 1)

Simplify

tan^{2} (3 x) + 1 : sec^{2} (3 x)

= \frac{d}{d x} (sec^{2} (3 x))

Apply the chain rule:

2 sec (3 x) \frac{d}{d x} (sec (3 x))

= 2 sec (3 x) \frac{d}{d x} (sec (3 x))

\frac{d}{d x} (sec (3 x)) = sec (3 x) tan (3 x) \cdot 3

= 2 sec (3 x) sec (3 x) tan (3 x) \cdot 3

Simplify

2 sec (3 x) sec (3 x) tan (3 x) \cdot 3 : 6 sec^{2} (3 x) tan (3 x)

= 6 sec^{2} (3 x) tan (3 x)

y^{^{''}} + 9 y = 3 t^{2}

π \cdot x^{\frac{1}{2}} - x^{\frac{1}{3}}

- 4 sin (x)

\frac{d}{d b} (sin^{4} (2 b) - cos^{4} (2 b))

2 x^{2} y - x^{3} y^{^{'}} = y^{3}

What is the derivative of tan^2(3x)+1 ?
The derivative of tan^2(3x)+1 is 6sec^2(3x)tan(3x)
What is the first derivative of tan^2(3x)+1 ?
The first derivative of tan^2(3x)+1 is 6sec^2(3x)tan(3x)