What is (\partial)/(\partial x)(x+2y+1) ?

The answer to (\partial)/(\partial x)(x+2y+1) is 1

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(\partial)/(\partial x)(x+2y+1)

\frac{\partial}{\partial x} (x + 2 y + 1)

1

Solution steps

\frac{\partial}{\partial x} (x + 2 y + 1)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (2 y) + \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (2 y) = 0

\frac{\partial}{\partial x} (1) = 0

= 1 + 0 + 0

Simplify

= 1

h \to 0 lim (\frac{( 2 + h ) ^{2} - 8}{h})

\frac{\partial}{\partial x} (ln (x^{2}))

\frac{\partial}{\partial z} (x z - 5 x^{2} y^{3} z^{4})

\int (\frac{3}{x} - \frac{5}{x ^{6}}) d x

\frac{d y}{d x} = \frac{x ^{3} - x ^{2} + x}{x}

What is (\partial)/(\partial x)(x+2y+1) ?
The answer to (\partial)/(\partial x)(x+2y+1) is 1