What is the limit as x approaches-0.00000001 of x^x ?

The limit as x approaches-0.00000001 of x^x is 1/((-0.00000001)^{0.00000001)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches-0.00000001 of x^x

x \to - 0.00000001 lim (x^{x})

\frac{1}{( - 0.00000001 ) ^{0.00000001}}

Solution steps

x \to - 0.00000001 lim (x^{x})

Plug in the value

x = - 0.00000001

= (- 0.00000001)^{- 0.00000001}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{( - 0.00000001 ) ^{0.00000001}}

f (x) = [x + (x + sin^{2} (x))^{3}]^{4}

f (x) = x^{2} + 5 - 3 x^{- 2}

x \to \infty lim ((\frac{13 x}{13 x + 3})^{5 x})

\int \frac{2 x - 4}{( x ^{2} - 4 x + 7 ) ^{2}} d x

(- 2)^{t - 1}

What is the limit as x approaches-0.00000001 of x^x ?
The limit as x approaches-0.00000001 of x^x is 1/((-0.00000001)^{0.00000001)}