What is the derivative of f(x)=3e^x+2/(\sqrt[3]{x)} ?

The derivative of f(x)=3e^x+2/(\sqrt[3]{x)} is 3e^x-2/(3x^{4/3)}

What is the first derivative of f(x)=3e^x+2/(\sqrt[3]{x)} ?

The first derivative of f(x)=3e^x+2/(\sqrt[3]{x)} is 3e^x-2/(3x^{4/3)}

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derivative of

3 e^{x} - \frac{2}{3 x ^{\frac{4}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (3 e^{x}) = 3 e^{x}

= 3 e^{x} - \frac{2}{3 x ^{\frac{4}{3}}}

\int (arcsin (x))^{2} d x

g (x) = \frac{2}{x ^{3}} - \frac{1}{x ^{2}}

\frac{d y}{d x} = x + x y^{2}

f (x) = x^{3 x}

(t + 2 y + 3) + (2 t + 4 y - 1) \frac{d y}{d t} = 0

What is the derivative of f(x)=3e^x+2/(\sqrt[3]{x)} ?
The derivative of f(x)=3e^x+2/(\sqrt[3]{x)} is 3e^x-2/(3x^{4/3)}
What is the first derivative of f(x)=3e^x+2/(\sqrt[3]{x)} ?
The first derivative of f(x)=3e^x+2/(\sqrt[3]{x)} is 3e^x-2/(3x^{4/3)}