What is the derivative of F(x)= 3/(1+x^2) ?

The derivative of F(x)= 3/(1+x^2) is -(6x)/((1+x^2)^2)

What is the first derivative of F(x)= 3/(1+x^2) ?

The first derivative of F(x)= 3/(1+x^2) is -(6x)/((1+x^2)^2)

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derivative of

F (x) = \frac{3}{1 + x ^{2}}

- \frac{6 x}{( 1 + x ^{2} ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{3}{1 + x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{1}{1 + x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d x} ((1 + x^{2})^{- 1})

Apply the chain rule:

- \frac{1}{( 1 + x ^{2} ) ^{2}} \frac{d}{d x} (1 + x^{2})

= - \frac{1}{( 1 + x ^{2} ) ^{2}} \frac{d}{d x} (1 + x^{2})

\frac{d}{d x} (1 + x^{2}) = 2 x

= 3 (- \frac{1}{( 1 + x ^{2} ) ^{2}} \cdot 2 x)

Simplify

3 (- \frac{1}{( 1 + x ^{2} ) ^{2}} \cdot 2 x) : - \frac{6 x}{( 1 + x ^{2} ) ^{2}}

= - \frac{6 x}{( 1 + x ^{2} ) ^{2}}

\int 3 x - 5 d x

\frac{\partial}{\partial z} (x^{2} y)

x \to π lim (+ (ln (sin (x))))

\frac{\partial}{\partial x} (\frac{x}{x ^{5} - y ^{3}})

\frac{d}{d x} (- 2 x - 1)

What is the derivative of F(x)= 3/(1+x^2) ?
The derivative of F(x)= 3/(1+x^2) is -(6x)/((1+x^2)^2)
What is the first derivative of F(x)= 3/(1+x^2) ?
The first derivative of F(x)= 3/(1+x^2) is -(6x)/((1+x^2)^2)