What is the derivative of sqrt(x^2-2x+1) ?

The derivative of sqrt(x^2-2x+1) is 1

What is the first derivative of sqrt(x^2-2x+1) ?

The first derivative of sqrt(x^2-2x+1) is 1

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\frac{d}{d x} (x^{2} - 2 x + 1)

1

Solution steps

\frac{d}{d x} (x^{2} - 2 x + 1)

Apply the chain rule:

\frac{1}{2 x ^{2} - 2 x + 1} \frac{d}{d x} (x^{2} - 2 x + 1)

= \frac{1}{2 x ^{2} - 2 x + 1} \frac{d}{d x} (x^{2} - 2 x + 1)

\frac{d}{d x} (x^{2} - 2 x + 1) = 2 x - 2

= \frac{1}{2 x ^{2} - 2 x + 1} (2 x - 2)

Simplify

\frac{1}{2 x ^{2} - 2 x + 1} (2 x - 2) : 1

= 1

\int \frac{ln ( 11 x )}{x} d x

x \to 5 lim (cos (\frac{π x}{3}))

\frac{d}{d x} (sin (x - \frac{π}{6}))

\int \frac{x}{( x ^{2} - 1 ) ( x - 2 )} d x

(4 t^{4} + \frac{4}{t ^{4}})^{\frac{1}{4}}

What is the derivative of sqrt(x^2-2x+1) ?
The derivative of sqrt(x^2-2x+1) is 1
What is the first derivative of sqrt(x^2-2x+1) ?
The first derivative of sqrt(x^2-2x+1) is 1