What is the derivative of x^2+3x ?

The derivative of x^2+3x is 2x+3

What is the first derivative of x^2+3x ?

The first derivative of x^2+3x is 2x+3

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derivative of

x^{2} + 3 x

2 x + 3

Solution steps

\frac{d}{d x} (x^{2} + 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (3 x)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

= 2 x + 3

\frac{d ^{2} y}{d t ^{2}} - 2 \frac{d y}{d t} - 8 y = 0

\frac{d}{d x} ((x^{3} + 2 x - 5)^{2})

ln (1 - 2 x)

\int_{- π}^{π} e^{x} d x

\frac{d}{d x} (x^{4} (3 - x)^{3})