What is the derivative of ln((x-1^2)) ?

The derivative of ln((x-1^2)) is 2/(x-1)

What is the first derivative of ln((x-1^2)) ?

The first derivative of ln((x-1^2)) is 2/(x-1)

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\frac{d}{d x} (ln ((x - 1)^{2}))

\frac{2}{x - 1}

Solution steps

\frac{d}{d x} (ln ((x - 1)^{2}))

Apply the chain rule:

\frac{1}{( x - 1 ) ^{2}} \frac{d}{d x} ((x - 1)^{2})

= \frac{1}{( x - 1 ) ^{2}} \frac{d}{d x} ((x - 1)^{2})

\frac{d}{d x} ((x - 1)^{2}) = 2 (x - 1)

= \frac{1}{( x - 1 ) ^{2}} \cdot 2 (x - 1)

Simplify

\frac{1}{( x - 1 ) ^{2}} \cdot 2 (x - 1) : \frac{2}{x - 1}

= \frac{2}{x - 1}

x = 3 y, x = y^{2} - 4

\int x^{2} e^{- λ x} d x

\int_{0}^{1} \frac{3}{1 + t ^{2}} d t

\frac{d}{d θ} (3 - sin (θ))

f (x) = x^{2} - 4, at x = 0

What is the derivative of ln((x-1^2)) ?
The derivative of ln((x-1^2)) is 2/(x-1)
What is the first derivative of ln((x-1^2)) ?
The first derivative of ln((x-1^2)) is 2/(x-1)