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Popular >

y^'=8+t-y

Solution

y^{^{'}} = 8 + t - y

Solution

y = t + 7 + \frac{c _{1}}{e ^{t}}

Solution steps

y^{'} (t) = 8 + t - y

Solve linear ODE:

y = t + 7 + \frac{c _{1}}{e ^{t}}

y = t + 7 + \frac{c _{1}}{e ^{t}}

Popular Examples

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3^{s i n (x)}

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\int \frac{1}{8} e^{8 x} d x

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\frac{d}{d x} (9 (2 x e^{x} + e^{x} x^{2}))

integral from 1 to 4 of 5/x

\int_{1}^{4} \frac{5}{x} d x

integral of x^2(1/(x^3)+1/(sqrt(x)))

\int x^{2} (\frac{1}{x ^{3}} + \frac{1}{x}) d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=8+t-y ?
The solution for y^'=8+t-y is y=t+7+(c_{1})/(e^t)