What is (\partial)/(\partial x)(-2x^2y-y) ?

The answer to (\partial)/(\partial x)(-2x^2y-y) is -4xy

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(\partial)/(\partial x)(-2x^2y-y)

\frac{\partial}{\partial x} (- 2 x^{2} y - y)

- 4 x y

Solution steps

\frac{\partial}{\partial x} (- 2 x^{2} y - y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (2 x^{2} y) - \frac{\partial}{\partial x} (y)

\frac{\partial}{\partial x} (2 x^{2} y) = 4 y x

\frac{\partial}{\partial x} (y) = 0

= - 4 y x - 0

Simplify

= - 4 x y

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\int \frac{1}{x ^{2} + 625} d x

x \to 0 lim (\frac{∣ x ∣}{x ^{3} - 5})

y = 8 x^{2} - 5 x^{11}

\int (x - 2) e^{x + 3} d x

What is (\partial)/(\partial x)(-2x^2y-y) ?
The answer to (\partial)/(\partial x)(-2x^2y-y) is -4xy