What is area y= x/3 ,y=sqrt(x-2) ?

The answer to area y= x/3 ,y=sqrt(x-2) is 1/6

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area y= x/3 ,y=sqrt(x-2)

area

y = \frac{x}{3}, y = x - 2

\frac{1}{6}

Solution steps

Apply the area formula:

\int_{3}^{6} \frac{x}{3} - x - 2 d x

Solve

\int_{3}^{6} \frac{x}{3} - x - 2 d x : \frac{1}{6}

The area is:

= \frac{1}{6}

\frac{d}{d x} (2 x^{2} + 4 x + 5)

e^{x + 3 y} d y = x d x

\int \frac{8}{x ^{2} + 1} d x

\int \frac{x ^{2}}{x ^{2} + 2 x + 2} d x

\frac{\partial}{\partial x} (x + 2 y - 1)

What is area y= x/3 ,y=sqrt(x-2) ?
The answer to area y= x/3 ,y=sqrt(x-2) is 1/6