What is the limit as x approaches infinity of 2^x+1 ?

The limit as x approaches infinity of 2^x+1 is infinity

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limit as x approaches infinity of 2^x+1

x \to \infty lim (2^{x} + 1)

\infty

Solution steps

x \to \infty lim (2^{x} + 1)

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to \infty lim (2^{x}) + x \to \infty lim (1)

x \to \infty lim (2^{x}) = \infty

x \to \infty lim (1) = 1

= \infty + 1

Apply Infinity Property:

\infty + c = \infty

= \infty

x \to - 2 lim (f (x))

\int_{- 3}^{3} x^{2} - 9 d x

(x sec (\frac{y}{x}) + y) d x - x d y = 0

y = \frac{2 ^{x}}{2} + \frac{12}{x}

f (x) = 5 e^{4 x} + e^{- x^{2}}, at x = 1

What is the limit as x approaches infinity of 2^x+1 ?
The limit as x approaches infinity of 2^x+1 is infinity