What is the solution for (dy)/(dx)=e^{(3x+2y)} ?

The solution for (dy)/(dx)=e^{(3x+2y)} is y=-(ln(-2/3 e^{3x}-c_{1}))/2

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(dy)/(dx)=e^{(3x+2y)}

\frac{d y}{d x} = e^{(3 x + 2 y)}

y = - \frac{ln ( - \frac{2}{3} e ^{3 x} - c _{1} )}{2}

Solution steps

\frac{d y}{d x} = e^{(3 x + 2 y)}

Solve separable ODE:

y = - \frac{ln ( - \frac{2}{3} e ^{3 x} - c _{1} )}{2}

y = - \frac{ln ( - \frac{2}{3} e ^{3 x} - c _{1} )}{2}

f (x) = x^{2} + 3 x, at x = 1

\frac{d}{d x} (4 - \frac{15}{4 x ^{\frac{1}{4}}})

\frac{d}{d x} (x^{3} + 3 x^{2} - 8)

\int 3 cos^{3} (2 x) d x

e^{x} cos (x)

What is the solution for (dy)/(dx)=e^{(3x+2y)} ?
The solution for (dy)/(dx)=e^{(3x+2y)} is y=-(ln(-2/3 e^{3x}-c_{1}))/2