What is the limit as x approaches 1 of 2x^2-4x+7 ?

The limit as x approaches 1 of 2x^2-4x+7 is 5

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limit as x approaches 1 of 2x^2-4x+7

x \to 1 lim (2 x^{2} - 4 x + 7)

5

Solution steps

x \to 1 lim (2 x^{2} - 4 x + 7)

Plug in the value

x = 1

= 2 \cdot 1^{2} - 4 \cdot 1 + 7

Simplify

= 5

\frac{10}{16 s ^{2} + 5 s + 1}

\frac{\partial}{\partial x} (x^{2} + 4 y^{2} + 5 z^{2})

f (x) = \frac{7}{10} x^{2} + 4 x^{3}

\frac{d p}{p - p ^{2}} = d t

\frac{d}{d x} (3 x^{4} + 2 x^{3} + x^{2} - 2)

What is the limit as x approaches 1 of 2x^2-4x+7 ?
The limit as x approaches 1 of 2x^2-4x+7 is 5