What is the derivative of 1+1/(4x) ?

The derivative of 1+1/(4x) is -1/(4x^2)

What is the first derivative of 1+1/(4x) ?

The first derivative of 1+1/(4x) is -1/(4x^2)

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\frac{d}{d x} (1 + \frac{1}{4 x})

- \frac{1}{4 x ^{2}}

Solution steps

\frac{d}{d x} (1 + \frac{1}{4 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (\frac{1}{4 x})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (\frac{1}{4 x}) = - \frac{1}{4 x ^{2}}

= 0 - \frac{1}{4 x ^{2}}

Simplify

= - \frac{1}{4 x ^{2}}

\frac{1}{10} e^{4 t} + \frac{9}{10} e^{- 6 t}

f (x) = 2 x^{2} - 16 x + 35

\int (- 3 x + 4 x) d x

d y - (y - 7)^{2} d x = 0

\int e^{4 x} cos (2 x) d x

What is the derivative of 1+1/(4x) ?
The derivative of 1+1/(4x) is -1/(4x^2)
What is the first derivative of 1+1/(4x) ?
The first derivative of 1+1/(4x) is -1/(4x^2)