What is the integral from-infinity to 20 of re^{r/5} ?

The integral from-infinity to 20 of re^{r/5} is 75e^4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-infinity to 20 of re^{r/5}

\int_{- \infty}^{20} r e^{\frac{r}{5}} d r

75 e^{4}

Solution steps

\int_{- \infty}^{20} r e^{\frac{r}{5}} d r

Compute the indefinite integral:

\int r e^{\frac{r}{5}} d r = 5 e^{\frac{r}{5}} r - 25 e^{\frac{r}{5}} + C

Compute the boundaries:

\int_{- \infty}^{20} r e^{\frac{r}{5}} d r = 75 e^{4} - 0

= 75 e^{4} - 0

Simplify

= 75 e^{4}

\int \frac{2 x + 1}{x + 1} d x

\int - 1 ln (x^{2} - 1) d x

y^{^{'}} = \frac{2 x}{1 + 2 y}, y (0) = 2

\int sec (\frac{x}{5}) d x

\frac{1}{s ( s ^{2} + 5 s + 6 )}

What is the integral from-infinity to 20 of re^{r/5} ?
The integral from-infinity to 20 of re^{r/5} is 75e^4