What is (\partial)/(\partial x)(4x^{4y}) ?

The answer to (\partial)/(\partial x)(4x^{4y}) is 16yx^{4y-1}

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(\partial)/(\partial x)(4x^{4y})

\frac{\partial}{\partial x} (4 x^{4 y})

16 y x^{4 y - 1}

Solution steps

\frac{\partial}{\partial x} (4 x^{4 y})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{\partial}{\partial x} (x^{4 y})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 \cdot 4 y x^{4 y - 1}

Simplify

= 16 y x^{4 y - 1}

\int (- 16 cos (2 t)) d t

\int (\frac{sin ( x )}{cos ( x )}) d x

\frac{d}{d x} (\frac{y - x ^{2} + 2}{x - y})

y^{^{'}} = \frac{y ^{2} + 2}{x y - 4 y}

\frac{\partial}{\partial x} (x y e^{4 y})

What is (\partial)/(\partial x)(4x^{4y}) ?
The answer to (\partial)/(\partial x)(4x^{4y}) is 16yx^{4y-1}